The Fourth Trumpet

The ability to find a third part from different octals according to the second and third trumpets is not universal. If we start with an octal and write out the "fire" column,

a = [0,b,d,f] = [0,c,e,g]
b = [0,c,d,g] = [0,a,e,f]
d = [0,c,e,f] = [0,a,b,g]
c = [0,a,f,g] = [0,b,d,e]
f = [0,b,e,g] = [0,a,c,d]
g = [0,a,d,e] = [0,b,c,f]
e = [0,a,b,c] = [0,d,f,g]

and then make a second generation fire column based on a different left/right subgroup association of the "fire" octal

a = [0,b,d,e] = [0,c,f,g]
b = [0,d,f,g] = [0,a,c,e]
d = [0,c,e,g] = [0,a,b,f,]
g = [0,a,e,f] = [0,b,c,d]
e = [0,b,c,f] = [0,a,d,g]
f = [0,a,c,d] = [0,b,e,g]
c = [0,a,b,g] = [0,d,e,f]

and then make a third generation similarly

a = [0,b,c,d] = [0,e,f,g]
b = [0,c,f,g] = [0,a,d,e]
c = [0,d,e,f] = [0,a,b,g]
f = [0,a,d,g] = [0,b,c,e]
d = [0,b,e,g] = [0,a,c,f]
g = [0,a,c,e] = [0,b,d,f]
e = [0,a,b,f] = [0,c,d,g]

Then we will not find the associations hold between subgroups as we did with the "blood" of the second trumpet. I.e., although [0,b,d,f] appears in the third generation fire column, it is not truly in agreement with the first left handed column, i.e. g = [0,b,d,f] in the latter, but not as the former, since we started with a=[0,b,d,f]. We cannot use the same associations. (The blood or intersection does not appear.)

So, if we equate the first generation octal with the sun, the second as the moon and the third as the stars, (I.e. the sun does not shine at night, and the stars not by day: but the moon shines in both) Then there is no "blood" to find in all three as with the second trumpet. There is a third between the first and second generations in f = [0,b,e,g] and between the second and third in c = [0,d,e,f] but then, the "blood" is missing between generations one and three - so a third part of the sun, moon and stars is "smitten" and there is no product (as a resultant third part of the other two) or association unique to these three.

So we can say the "day" the pairing of the sun and moon does not shine for a third (the stars are missing), and the pairing of the moon and stars does not shine for a third either (no sun at night). Take a look at this table... I have used the letter "E" for "there exists an intersection." Note the missing "E" in the Moon/Moon association. This is taken to mean that the moon will appear with the Sun or the stars, but never on its own as both left and right. (The moon has no light of its own to shine as the Sun or Stars.) (There is no relation to fit between the sun and stars, on its own the moon is as "a sun" albeit a generation removed.)


The first and last columns would represent the "day" and "night" so we find that the day does not shine for a third of it and the night likewise. The products become either non-existent or completely arbitrary: There is no apparent association to pick a unique "fourth" group as in the wormwood case.

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