Revelation

The Book, The Lamb, The Right
The "right hand" of God we equate with the "sun" octal comprised of the K4 subgroups {(a,b,c), (a,d,e), (a,f,g), (b,d,f), (b,e,g), (c,e,f), (c,d,g)}. This includes the both the elements and the operation; so also as part of the "right hand" we should treat this as {0,a,b,c,d,e,f,g} or the octal group. The seven multiplicative elements {1,b,c,d,e,f,g} if "a" is unity are also in "the right hand".
The left hand varies according to the unity element and the static subgroup held fixed. The left hand is also an octal group: the division of elements we saw elsewhere divides the groups differently according to the choice of unity element. We may have in one case:
a=1 => [b,d,f] and {c,e,g} is static
b=1 => [c,d,g] and {a,e,f} is static
d=1 => [c,e,f] and {a,b,g} is static
c=1 => [a,f,g] and {b,d,e} is static
f=1 => [b,e,g] and {a,c,d} is static
g=1 => [a,d,e] and {b,c,f} is static
e=1 => [a,b,c] and {d,f,g} is static
Then the column in {...} is the left handed octal. We should note that if we start in the top row with c=1 using the seven cycle (c,b,d,a,f,e,g) then:
c=1 => [b,d,f] and {a,e,g} is static
b=1 => [a,d,e] and {c,f,g} is static
d=1 => [a,f,g]
and {b,c,e} is static
a=1 => [c,e,f] and {b,d,g} is static
f=1 => [b,e,g] and {a,c,d} is static
e=1 => [c,d,g] and {a,b,f} is static
g=1 => [a,b,c] and {d,e,f} is static
And the left hand {...} groups form a different octal. (We did shift seven cycle groups here.)
The book contains every place that may be occupied in heaven by those that the Lord has chosen. The seals upon the book, (which sits at the right hand) correspond to shifting the unity element through the right hand or "sun" octal whilst preserving the original static subgroup (say [b,d,f]) in place. Analogously we see that upon unity there are six further possibilities "for unity": Then the 24 elders (that represent the forms of GF(8)) of the original unity in place have 6 further "possible places" giving us 144 places "sealed" within the book.
The "Lion of the tribe of Judah" approaches this book as if He were simply the unity element. The first four seals are perhaps easily unsealed by "any" unity element, however the Lamb that is "as slain" before the throne represents Christ with "two parts cut off" from the static subgroup (which is the lamb) as if it contained the unity element. (Which is not possible in the octal group even under the frobenius map.) The result is that in order to unseal the last three seals the Lamb must have the same K4 structure (of the static subgroup) of the octal, and have "life in Himself" to exist apart from the octal, as necessarily existent on it's own.
By "same K4 structure" we mean the same elements of the octal: not just an "isomorphic copy". ie [b,d,f] if a=1 using (a,b,d,c,f,g,e).
Then the last three seals are opened in a similar reduction to a smaller field  as from the octal or GF(8) to the K4 or GF(4) finite field. The last three seals are opened in K4 which though it appears "as slain" in the octal with two elements struck off, in His own form (of the trinity existing bodily) as Christ, the "Lion of the tribe of Judah" prevails to open the book, and is the one name in heaven that may do so  that has agreement with the exact same elements in the Father's octal (here [b,d,f] as above in the first row.)
So we see the octal {0,a,b,c,d,e,f,g} with a=1 and {b,d,f} fixed is in view to start: and the seals corresponding to {a,c,e,g} are easily opened. However the last three may not be done!
That is, unless we shift from the Lion to the Lamb to the field GF(4). Then; [0,b,d,f] easily provides the correct structure to open the last three seals {b,d,f}.
ie: with "b" as unity and [b,d,f] static we may form in using (A v B)^c a copy of GF(4) (with multiplication from frobenius upon the octal elements);
b = [b,d,f] = unity or static
d = [b,e,g]
f = [a,b,c]
The order that the seals are opened correspond to the seven eyes of the Lamb (being the seven Spirits of God), and the order that the static subgroups (corresponding to the current choice of unity element (seal)) cycle under multiplication (c.f. c=1 => [a,f,g] etc.) The seven subgroups correspond to the horns of the Lamb.
Of course one would ask, "why not reduce to GF(2)?" The answer is that this reduces the problem to that of the Holy Spirit, These are present in the seven lamps of fire before the throne. By equating these elements with the multiplicative elements of GF(8)* we have to realise that GF(4) is not a subfield of GF(8). Christ is not His Father, although appropriately the Holy Trinity is structurally sound as three separate persons!
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